0=3x^2-10x+5

Solution for 0=3x^2-10x+5 equation:

0=3x^2-10x+5

We move all terms to the left:

0-(3x^2-10x+5)=0

We add all the numbers together, and all the variables

-(3x^2-10x+5)=0

We get rid of parentheses

-3x^2+10x-5=0

a = -3; b = 10; c = -5;
Δ = b2-4ac
Δ = 102-4·(-3)·(-5)
Δ = 40
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{40}=\sqrt{4*10}=\sqrt{4}*\sqrt{10}=2\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{10}}{2*-3}=\frac{-10-2\sqrt{10}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{10}}{2*-3}=\frac{-10+2\sqrt{10}}{-6}
$